Point masses $m_1$ and $m_2$ are placed at the opposite ends of a rigid rod of length $L$, and negligible  mass. The rod is to be set rotating about an axis perpendicular to it. The position of point $P$ on this rod through which the axis should pass so that the work required to set the rod rotating with angular velocity $\omega_0$ is minimum, is given by

806-390

  • [AIPMT 2015]
  • A

    $x= $$\frac{{{m_2}L}}{{{m_1} + {m_2}}}$

  • B

    $x=$ $\frac{{{m_1}L}}{{{m_1} + {m_2}}}$

  • C

    $x= $$\frac{{{m_1}L}}{{{m_2}}}$

  • D

    $x=$$\frac{{{m_2}L}}{{{m_1}}}$

Similar Questions

A solid cylinder length is suspended symmetrically through two massless strings, as shown in the figure. The distance from the initial rest position, the cylinder should by unbinding the strings to achieve a speed of $4\,ms ^{-1}$, is$........cm$. $\left(\right.$ take $\left.g=10\,ms ^{-2}\right)$

  • [JEE MAIN 2022]

$A$ uniform rod of length $l$, hinged at the lower end is free to rotate in the vertical plane . If the rod is held vertically in the beginning and then released, the angular acceleration of the rod when it makes an angle of $45^o$ with the horizontal ($I = ml^2/3$)

The moment of inertia of a body about a given axis is $1.2 \;kg m^{2}$. Initially, the body is at rest. In order to produce a rotational kinetic energy of $1500\; joule$, an angular acceleration of $25 \;rad s^{-2}$ must be applied about that axis for a duration of

  • [AIPMT 1990]

One end of rod of length $L$ is on horizontal plane. It is inclined at angle $\alpha$ to  horizontal plane. When released its angular velocity after coming to horizontal plane is 

$A$ rod hinged at one end is released from the horizontal position as shown in the figure. When it becomes vertical its lower half separates without exerting any reaction at the breaking point. Then the maximum angle $‘\theta ’$ made by the hinged upper half with the vertical is ......... $^o$.